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Every element of the codomain of f is an output for some input. We can detect whether a linear transformation is one-to-one or onto by inspecting the columns of its standard matrix (and row reducing). Theorem. Suppose T : Rn Rm is the linear transformation T(v) = Av where A is an m × n matrix.
2:02 5:18 Suggested clip Linear Algebra Example Problems — Onto Linear Transformations YouTubeStart of suggested client of suggested clip Linear Algebra Example Problems — Onto Linear Transformations
Definition(Onto transformations) A transformation T : R n R m is onto if, for every vector b in R m, the equation T (x)= b has at least one solution x in R n.
A matrix transformation is onto if and only if the matrix has a pivot position in each row. Row-reduce it and then verify if the number of pivots is equal to the number of rows.
Suppose that T:UV T : U V is a linear transformation. Then T is subjective if and only if the range of T equals the codomain, R(T)=V R (T) = V.
0:12 3:43 Suggested clip How to Prove a Function is Subjective(Onto) Using the Definition YouTubeStart of suggested client of suggested clip How to Prove a Function is Subjective(Onto) Using the Definition
To show that g f is injective, we need to pick two elements x and y in its domain, assume that their output values are equal, and then show that x and y must themselves be equal. Let's splice this into our draft proof. Remember that the domain of g f is A and its co-domain is C. Proof: Let A, B, and C be sets.
And then if the rank is equal to the amount of column of the matrix, then it is injective. If the rank equals to the amount of rows of the matrix, then it is subjective. If rank = amount of rows = amount of column then it's bijective.
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