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Here is a set of three problems they areal dealing with section 1.6 which dissolving inequalities we#39;relooking at single inequalities where you have oneness than or greater than sign and thence also are looking at compound inequalities, so the directions for these three problems are to solve and then when you#39’re done solving draw a small graph or sketch so we#39’re going to start with the first one on the Left we want to solve this first thing you want to do we#39’re going to distribute the 4thirds so we#39’re going to take the four thirds here and here, so we get four thirds x minus when you take four thirds times six you get 8 plus 2 less than or equal to 5 combines like terms, so we have four thirds x minus 6 is less than or equal to 5 add 6 to both sides four thirds x is less than or equal to 11 and finally to get rid of the four thirds#39’re going to multiply by its reciprocal three-fourths we get x islets than or equal to thirty-three fourths you can leave it as 33 force doesn't#39’t reduce your graph is any very basic all IN#39’m looking for on your number line is that you put the point thatyou'’re dealing with thirty-three fourths you put the correct type of circle in this case it is a closed circle because you have the or equal to here and thence are looking at all numbers that airless than or equal to, so we want to shade or draw an arrow to the left and that will get you full credit for the graph for the second one this is compound inequality because you have more than one inequality sign this miscalled an and inequality, and they can resolve all at once you#39;relooking in the middle to see what you need to do you need to add for what you do in the middle you do on both the left and the right side, so you actually put a plus for three places it too is less than 2 Xis less than or equal to 11 last steps is divide everything by 2, so you can get the X by itself in the middle, so you have 1 is less than x is less than or equal to 11 hands when you#39’re checking acompoundequality and inequality what you want to look for is that both inequalities appointing the same direction they cannot have one pointing left and one pointing left right, and they have to be pointing towards the number that is smaller that will help you catch your mistakes on your number line you#39’re going to put 1and 11 halves I'm done#39’t not going to get picky on how far apart you're done#39’t have touted all the numbers in between we haven't open circle at one a closed circle at11 hams, and we are shading or connecting in between that tells me that any number between 1 and 11 halves including 11halves would be a solution to your inequality the last one up here is confident equality or inequality you#39’ll actually see the word or with these are two separate inequalities they may be almost identical they may be completely different like this one you solve them separately the only thing that works together as you draw one graph so for this place you start...
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