Note Over Equation Release For Free
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Below is a list of the most common customer questions. If you can’t find an answer to your question, please don’t hesitate to reach out to us.
How can I get my height after t seconds?
The equation for the object's height s at time t seconds after launch is s(t) = 4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground?
What is the height of the ball after 1 second?
After 1 second, h = 64(1) — 32(1^2) making h = 32 ft.
What is the height of the ball after 2 seconds?
, this means that the height of the ball after 2 seconds is 12.4 meters. The -4.9t^2 is the force of gravity pulling it down and the 15t is the ball being thrown keeping it up.
What is the maximum height of the ball?
Therefore, if a ball is thrown directly upward from an initial height of 200 feet with an initial velocity of 96 feet per second, after 3 seconds it will reach a maximum height of 344 feet.
What will be the height of the ball after 2 seconds?
, this means that the height of the ball after 2 seconds is 12.4 meters. The -4.9t^2 is the force of gravity pulling it down and the 15t is the ball being thrown keeping it up.
How high is the ball after 1 second?
After 1 second, h = 64(1) — 32(1^2) making h = 32 ft.
How do you find the height of an object thrown straight up?
An object is thrown straight up from the top of a building h feet tall with an initial velocity of v feet per second. The height of the object as a function of time can be modeled by the function h(t) = 16t2 + VT + h, where h(t) is the height of the object (in feet) t seconds after it is thrown.
How many seconds does it take for the golf ball to hit the ground?
The ball hits the ground after 4 seconds.
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