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So we say that there are 5 factorial = 5! = 5×4x3×2x1 = 120 ways to arrange five objects. In general, we say that there are n! Permutations of n objects.
Thus you have made 5 × 4 A 3 A 2 1 = 120 choices and there are 120 possible 5-digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated. Now consider the possibilities with 13 as the first two digits.
The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999. You can generalize that: the number of N-digit combinations is 10 N.
0:37 2:14 Suggested clip How Many Combinations of Five Numbers Can Be Made Out of YouTubeStart of suggested client of suggested clip How Many Combinations of Five Numbers Can Be Made Out of
Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula NCR = n! / r! * (n — r)!, where n represents the total number of items, and r represents the number of items being chosen at a time.
The number of permutations of n distinct objects, taken r at a time is: Pr = n! / (n — r)! Thus, 210 different 3-digit numbers can be formed from the digits 1, 2, 3, 4, 5, 6, and 7.
1 Answer. Daniel L. There are 3,628,800 ways to arrange those letters. See explanation for details.
Ten (10) STUDENTS may be seated in a row 10! Ways. This is because each student can be seated in any of the 10 seats. So, there could be 3628800 possible arrangements.
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