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So calculating with significant digits for addition and subtraction is the same rule, so I'm only going to do a once, and I'm going to do it for addition, and then I'm going to give you some practice problems edition with SIG dicks significant digits, and you know some people call them SIG figs you can call them sick pigs if you want to it's all the same thing all right, but SIG dig SIG thinks just different ways of saying the same thing potato so let's work with the same rectangle as we had before it's got a length it's got a width we've got a length of 10.38 meters we've got a width we stated of 9.2 meters and if we're just going to do an addition process let's find the perimeter okay, so the question is or the requirement is too third to find the perimeter, and before we do find the perimeter before we do it I'll give you the rule the lowest number of decimal places in the measured values determines how many decimal places will be in the final answer so while the first one was about significant digits adding an array of multiplication division is with significant digits adding and subtracting is about decimal places so in this case if I want to find the perimeter I'll just write it out in full I'll say p equals l + l + w + w I'll write it the whole thing 10.38 meters plus nine point two meters plus nine point two meters we have a calculator that sounds right 39.1 six meters that's the unbounded value you know we always do the nun rounded value before we do our around it watch this round two any ideas look at their rule in orange what do you say no not 59 look at the decimal places yep sorry yeah it should run to the 10th in the 10th decimal place so 39.2 okay so let's say approximately equal to thirty-nine point two meters after having been rounded appropriately okay we'll always round appropriately at the end you should always by the way keep the unbounded value because you never know maybe there's like a Part B to this question where you want the undrowned value for future calculations I write down the unwound value then do your approx lets you and write you around buddy
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