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The same four five and eight and as you can guess free one and one there's no way to do it all right but then now we try to do in one all right well with two and one we're going to start the same place try an index of one with this if we take the 2 minus the one there's no solution we can't use that all right, but we can now go from 1 to 20 to all right with that we're going in the wrong direction because we have an index one taking us to an index of 2 all right so that fails next try going from using the second element all right so with this we if we use the two we can take and go over two minus two columns and with this that has a 1 I add 1 is less than two, so that's a suitable solution that is to solve for together a 1 in the two all right with this from this position this says use the element with index chip mm-hmm I fine we see it's a two so with this we could try and do two different things we could try to do 1-2 all right which is going to take us back to gross that's outside the table, so that's not how we did it the other way we can go is to take the second value and subtract that from the column so 2 minus two is zero and there we have an index of 12 networks so with this right, so we've covered the two by using the two now we're down to one and zero and to solve for one and zero using index on we can take and subtract one from the row to get 200 and that's the end of the road I kind of understand what you're saying, but I will need a lot to do a lot of ohs wow are you with it the thing is seeing what how little there is to the pattern all right because it's just it's the same pattern, but there are two ways you can go with it, you can go check you know go backwards in the columns, or you can go backwards in the rubs and how far you go depends on what value of s you're using all right now for one and three all right for one and three the notion is again well we could try using index want one it has a value of one and with this if I subtract one from the row that's a problem we're going from a 1 2 camp; 2 okay all right and that's so we try the other way, and we go from three to two, and again it's going the wrong way because we would have a one taking us to a two, so then we try the two with the two if we try to go backwards to in the rows were outside the table that's a problem, and then we could try going to and that takes us to a minus one that's a problem alright so that takes us to the three and with the three the notion is if we go back three and the roads right at the table and if we go back three in the columns that takes us to one and that's okay I think I kind of get it now all right men, but the idea is whenever you write down a value it means if you take the row and the column there is a solution using only those elements as we write this three down it means I can get some 21 and a some 23 just using values among these three up to that point up to that point of course we want to minimize the value that we write all right...
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