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Let#39’s do this problem now converting between Casey and KP, so this one says chemical engineer injects limestone into the hot flue gas and coal burning power plant to form line which scrubs sulfur dioxide from the gas and forms gypsum calcium sulfate die I find Casey for the following reaction if the carbon dioxide pressure ISN#39’t atmospheres so behave the formula that we were just given for the conversion of KP to kc right soil was an e equals kc x r t raised to the change of the number of moles of gas in the reaction okay so notice it#39’s just gas in general it doesn't#39’t matter what the identity of the actual gas is so if you want to come over here how do we do change in anything so the change in number of moles of gas is going to Bethe number of moles of gas final minus the number of moles of gas initial and so final number of moles of gas just from our balanced chemical equation harder#39’re just going to assume it#39’s a one tone to one ratio and so IN#39’m just going to save one mole, so one mole minus whatsit was how much gas do we have over here zero homes, so change is going to be one everybody okay with threes we#39’ve got KP and we#39;relooking for kc though, so we got to rearrange this equation let#39’s isolate Casey caseyequals k p divided by our teeth raised to the change in number of moles of dance okay, so we have KP 2 point 1 times10 of the negative 4/0.082 one liter ATM or one mole hill, and you have honestly done#39’t even have to expand it out because again we#39’re just going to kill all of our units in a second#39’ve got that raise to the one or one goal or whatever you want to say but again, although units are going to be killed so does anybody got to this point the next answer at least into that ones let#39’s just solve our problem now so okay, so this should go to two SIG figs, so I get two point six times ten to the negative six no units okay so remember why is this important because for reactions where gaseous products are formed, or you have gaseous reactants#39’s hard to figure out what the concentration is so if we do it this Wayne can figure out what the KC is through using the pressure readings from our manometer ok any questions on this one pretty straightforward right
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