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If you haven't#39’t done so yet make sure you pause the video and try to solve the question on your own first before listening on we can see from the graph that the acceleration is increasing Ashe position increases and from Newton#39;second law we know that the net force Conan object is equal to its mass times its acceleration well if the acceleration is increasing then that means that the net force also must be increasing and that means that in order to calculate the work we#39’re going to have to calculate the work done by a changing force or variable force again because the acceleration is changing that means tenet force is changing and so in order Roget the work we need to calculate it for a variable force and so let#39’s take look at the equation that we used to calculate the work done by a variable force and according to that equation to calculate the work all we need to do intake the integral of the force function from the initial position to the final position and of course we were not given force function in this question, but we'd know once again from Newton#39’s second law that the force would equal the mass multiplied by the acceleration of the object the problem with this equation right now is that we are integrating with respect to the variable X but inside the integral here the variables a and that#39’s basically an inconsistency in variables we#39’re not going to be able to easily integrate that, so the challenge becomes to replaced with an expression in terms of X and once we do that that means that our variable in the integral is going to Bethe same as the variable that we're reintegrating with respect to so let#39’s Glover to the graph and see if we configure out a way to express the acceleration in terms of X now the graphic that of a straight line, and we know that the equation of a straight line is basically y equals MX plus B in this case the y-axis is actually accelerations we can rewrite this as an equals MOB now B is the y-intercept and in this case it#39’s actually the intercept Andre can see from the graph that the intercept or the intercept is actually zero, so we can actually plug zero in for B which basically makes itdisappearnow we can actually find the value of Which is simply the slope but before wed that we have to figure out the values along the acceleration axis we were told that this highest value up here is equal to 20, so we do know that we also know that there are 1 2 3 4 spaces so if redivide 20 by 4 we get 5 and that means that each increment is 5, so we can label the rest of the axis here now to get the slope we can start at this point and pecan count up 5 10 and then go over 1 2 34, so the slope is up 10 over 4 and if we simplify that we get 2.5 so let#39’s come over here to our acceleration equation and plug in 2.5 for the slope we now have an expression for the acceleration in terms of X and that#39’s exactly what west out to do so what we#39’ll do is take that expression and plug it in for a so...
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