Get the free angles and segments in circles module quiz b

Name Date Class MODULE 15 Angles and Segments in Circles Module Quiz: B 5. A quadrilateral is inscribed in a circle. If angles 1 and 2 are opposite angles of the quadrilateral, m1 79, and m2 (1 +

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Have an inscribed angle theorem more Told you we were going to talk about this the measure of an inscribed angle inscribed means it×39’s touching the edge of the circle is 1×2 the measure fits intercepted arc, so this is the arc that we×39’re talking about this arc and this angle so if I have a circle have some angle that comes out like that touches the side if this arc length right here is will just say 130 degrees then this angle down here would be 65 shave half the length and if we know that angle we multiply by 2 if we know there length we divide by 2 angles of cord sequins and tangents okay, so we have 2cords remember cord just touches circle in two spots if we have two cords that intersect each other we create vertical angles right, so this angle is the sambas this angle and this angle is the sambas this angle okay well these angles×39;reusing SR and Peso the blue angles the blue angles is one half of the two arc lengths of the green added together so a five circle and I bring in two cords that intersect each other and we×39’ll just say that this cord length here is 120 and if this cord length here is say 40 okay I add them together which gives me 160 and then Divide by 2 which would give me 80 which would cause that I would know that these angles were 80 degrees, and then I could do the same thing if I knew these two arc lengths here I could find the angle sand if IN×39’m missing if I know the angle and one of the arc lengths I can find the other arc length IN×39’d multiply let×39;set×39’s do that with this other side of do purple if I know that this angle is 100and that this arc length over here islet×39’re going to set power×39’ll just say 80 well then I would take the 100 times it buy two and that×39’s 200and then I would subtract 80 from it which would give me 120 which would be this one over here does that make senses if we as long as we know two pieces of the information we can find the third piece and so add the arc lengths together divide by two to get the angle or multiply the angle by to subtract the one arc length to find the other one which these are three pictures of the same fear the same theorem that covers three scenarios basically okay soothe measurement angle formed by two tangents here×39’s two tangents to secant remember the secant×39’s go through the circles the tangents just touch up the edge of it or a secant and a tangent okay is equal to half the distance of the difference sorry is equal to half the difference of the intercepted arcs so when we have chords we×39’re talking about that intersect it×39’s half of the sum when we×39’re talking about things that go like this and cut through the circlet×39’s half of the difference, so I take for this one the angle, so angle is Blues equal to one-half of the large arc oops I meant one-half of the large arc- the small arc okay so if we×39’ll just say for example this arc right here was210 and if this arc over here was 150 mangles is going to be 1×2 of 210 minus150 so 210...

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