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Welcome to yet chemistry help calm my name is Dr. ken and in this video I'm going to work a few practice problems to accompany the lesson on heat and specific heat now also on get chemistry help calm you can print out a PDF worksheet of these exact problems, so you can follow along as I'm working them out so let's go ahead and jump right in question one says a car with magnesium wheels is parked in the Sun if the temperature rises from 22 degrees Celsius to 35 degrees Celsius how many MJ's of heat does each 6.8 kilogram wheel absorb and the specific heat is 1.0 to joules per gram degrees Celsius okay, so I've gone ahead, and I'm going to underline some important pieces of information here okay so when we're dealing with temperature heat mass etc the equation we're going to have to use is Q equals MCAT or Q equals M C delta T this is a reminder Q is heat M is mass C a specific heat which is a constant for a substance and delta T is the change in the temperature so let's go ahead just fill in what we know this is sometimes a useful way to start so Q M C + delta T so Q is the heat so that we don't know because it's asking me how many MJ's of heat and MJ is not Michael Jackson its mega joules now how about em that's mass so in our case the mass was given as six point eight kilograms now C is the is this specific heat that was given that's a constant so one point zero two joules per gram degree Celsius and delta T now remember that is the change in temperature which is the final minus the initial so in our case it said it went from 22 to 35 degrees Celsius, so final must be 35 minus initial must have been 22, so that would be a change of 30 okay so let's look here we want megajoules we've got kilograms joules per gram Celsius and Celsius okay now normally you have to set everything up to match whatever the units are on the specific heat so joules grams and degrees Celsius so the degrees Celsius we got the grams we don't have because our mass is in kilograms let's go ahead and convert kilograms into grams so as you might recall from our lesson on metric prefixes kilo means 10 to the third, so one kilo gram would be 10 to the third grams, so kilograms will cancel and that means our mass is six point eight times ten to the third grams okay, so now we've got joules grams and degree Celsius we've got grams got degrees Celsius okay, so we go ahead and solve for Q, and it will give it to us in joules then later on we can convert that to mega Joule so let's go ahead and plug that in so Q equals MC delta T so M is six point eight times 10 to the third grams C is one point zero two joules per gram degree Celsius and delta T we already solved and that was 13 degrees Celsius okay so let's see how everything oh how everything cancels out here sorry about that, so grams cancels Celsius cancels, so we're left with joules okay perfect so the answer I punch it in my calculator and I got 90,000 168 joules, but we don't want joules we want mega joules but first let's...
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