PA DoR REV-1196 2016 free printable template
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For more videos visit for the sake of education calm alright guys let's do this problem that says find the coordinate direction angles of the given force, so they give us the magnitude of F which is 75 pounds now we know that this force has an X component a Y component and a C component the C component is very easy to find is this force right here I mean this vector right here, and it's given by the magnitude of F sine of 30, and it's equal to 37 point 5 now we're going to find this vector form right here which is the projection of F along the X on Y plane, and it's easily given by F cos sine of 30 and this comes out to be 64 point 95 sorry this is actually negative because it's going down on the C axis now that we have this projection we can find the X component this component is given by the projection times the sine of 45 and the Y is given by the projection times the cosine of 45, but they're both the same because sine of 45 and cosine of 45 are the exact same thing, and they come out to be 45 point 93 45 point 93 both positive so the Cartesian vector form of F is 45 point ninety-three I plus 45 point 93 J minus thirty-seven point five K now they have the Cartesian vector form on the magnitude finding the angles is very easy three angles this is the angle that it forms with the X this is the angle that it forms with the Y and this is the angle that forms with the C, and they're given by the cosine inverse of the X component over the magnitude pair is given by the cosine numbers of the Y component over the magnitude and the cosine inverse of the C component over the magnitude, so this is the X component this is the Y component and this is the C component and this is the magnitude so with these four values you apply them into these three formulas, and you're going to get that the angles are fifty-two point two degrees 52 point two degrees and 120 degrees don't forget the negative sign when you plug in the C value, so this is the final answer for the direction R goes please comment below if you want me to do any problems, and I'll be happy to help thank you
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